Chemistry, asked by Ajeesh02, 2 days ago

The Fermi level of copper is at 7 eV. What is the density of states at this energy level? Give your answer in J−1m−3 . Choose the nearest value.

A) 3.1 x 1047


B) 3.5 x 1040


C) 5.5 x 1047


D) 1.1 x 1047​

Answers

Answered by Anonymous
0

Answer:

(a) From the Equation of fermi energy leads to

E=E

F

+kT in (P

−1

−1)=7.00eV +(8.62×10

−5

eV/K)(1000K)In(

0.900

1

−1)=6.81eV.

(b) N(E)=CE

1/2

=(6.81×10

27

m

−3

eV

−3/2

)(6.81eV)

1/2

=1.77×10

28

m

−3

.eV

−1

.  

(c) N

(E)=P(E)M(E)=(0.900)(1.77×10

8

m

−3

.ev)

−1

=1.59×10

28

m

−3

.eV

−1

.

Explanation:

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