The fifth and the 12th term of an arithmetic sequence are 20 and 104 respectively. Find the 22nd term.
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answer is here
Step-by-step explanation:
let the first term and common difference be a and d respectively
a + 11d = 104. (1)
a + 4d = 20 (2)
subtracting equation first and second
7d = 84
d = 12
and putting d= 12 in equation second,
a= -28
a22= -28+ 21*12
a22 = 224
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