The fifth part of a number when increased by 5 equals the fourth part decreased by 5. Find the number.
2. Find two consecutive natural numbers whose sum is 63.
3. Find two consecutive positive odd integers whose sum is 76.
4. Find three consecutive positive even integers whose sum is 90.
5. Divide 184 in three parts such that one third of one part may exceed one seventh of other part by 8.
Answers
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Answer:
1.200
2.32and 31
3.37 and 39
4.44 and 46
Step-by-step explanation:
Answer 1.
X=number
AS per problem
X/5+5=X/4-5
Solve and get X=200
Answer 2
Consecutive number can be x and x+1;
So x+x+1=63
X=31 and x+1=32
Answer 3
Two odd consecutive number can be 2x+1 and 2x+3
So 2x+1+2x+3=76
X=18
Then 2x+1=37 and 2x+3=39
Answer 4
Two even consecutive number can be 2xand 2x+2
So 2x+2x+2=90
X=22
So 2x =44 and 2x+2=46
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