Question

The fifth term from the end of the sequence 2, 6, 18,…, 39366 is​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

given,

A.P= 2 , 6 , 18 .................,39366

first term ( a1 ) = 2

common difference ( d ) = a2 - a1 = 6 - 2

= 4

last term a(n) = 39366

a (n) = a + ( n-1 ) d

39366 = 2 + ( n- 1 ) × 4

39366 - 2 = 4n - 4

39364 + 4 = 4n

39368 = 4n

n = 39368 / 4

n = 9842

hence, a ( 9842) = 39366

to find the fifth term from the end we have to substract 5 from the end ( n )

a ( n-5) = 9842 - 5

= 9837

therefore, the fifth term from the end of the sequence is *9837*