the fifth term in a sequence is 82 and the 12th is 103 find the first term and the common difference
Answers
Answered by
0
Answer:
A5=82----------(1), A12=103-------------(2)
a+4d=82--------(3), a+11d=103-----------(4)
subtract equation 3 & 4
a+11d=103
a+4d=82
- - -
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7d=21
d=21/7=3
d=3
putting this value in equation 1st
a+4d=82
a+4(3)=82
a+12=82
a=82-12=70
therefore first term is 70, and common difference is 3
Answered by
0
Answer:
first term,a = 70 and common difference,d =3
Step-by-step explanation:
Given:
a5= 82
a12=103
Explanation:
a5= a+4d
82=a+ 4d --- eqn 1
a12= a+11d
103= a+11d --- eqn 2
From equations 1 and 2 subtract 1 from 2
103=a+11d
82=a+4d
- - -
________
21=7d
d= 21/7
d=3
Putting d=3 in eqn 1 we have
a+4(3)=82
a+12=82
a=82-12
a=70
So, a=70 and d=3
AP is 70, -67, -64, -61........
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