Question

The fifth term of an A.P. is 26 and its 10th term is 51. Find the A.P.​

Answer 1

Answer:

Given,

a5=26

a10=51

a+4d=26-------(i)

a+9d=51--------(ii)

Equating eq.(i) from (ii) we get,

d=5

Now,

put the value of d in eq (i) i.e 5 we get,

a+4(5)=26

a+20=26

a=26-20=6

a=6

Now,

a15=a+14d

a15=6+14(5)

a15=6+70

a15=76

So,the A.P of 15th term is 76