The fifth term of an A.P. is 40 and the sev- enth term is 28 more than the 3rd term. Find the first and 10th term.
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Answer:
1st term= 12
10th term= 75
Step-by-step explanation:
a+6d=28+a+2d
Subtracting a from both sides and subtracting 2d from both sides,
6d-2d=28
4d=28
Dividing both sides by 4
d=7
5th term: a+4d
Substitute d=7
a+4d
=a+4(7)
=a+28
Since this is equal to 40,
a+28=40
a+28–28=40–28
a=12
1st term=12
10th term: a+ 9d
=12+9(7)
=12+63
=75
The 10th term is 75
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