Question

the fifth term of an AP is 26 and it's tenth term is 51.Find AP ​

Answer 1

Answer:

Step-by-step explanation:

Given, a +4d=26

a+9d=51

(by elemination method)

-5d=-25

d = 5

a+ 4d =26

a = 26-20

=6

Therefore AP = 6,11,16,21,26......

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Answer 2

Answer:

Step-by-step explanation:

an=a+(n–1)d

a5=a+(5–1)d

26=a+4d eq (1)

an=a+(n–1)d

a10=a+(10–1)d

51=a+9d eq(2)

From eq 1 and 2

51=a+9d

26=a+4d

=25 = 5d

25÷5 =d

d=5

26=a+4(5)

a+20=26

a=26–20

a=6

AP Is

a,a+d,a+2d.....

6,6+5,6+2(5)....

6,11,6+10....

6,11,16.....