the fifth term of an AP is 52 and it's twelfth term is 24.find AP
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Step-by-step explanation:
a5=52
a12=24
A. P=?
a+4d=52--------------eq1
a+11d=24--------------eq2
sub eq2 from eq1
7d=28
d=4
sub d in eq 1 or 2
there fore the A. P is
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