The fifth term of an AP is 52 and its twelfth term is 24. find AP Class X
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It is given here that :- fifth term of an AP is 52 and its twelfth term is 24
We know that a(n) = a +(n-1) d
So,
Fifth Term a(5) = a + (5-1)d
52 = a+4d (1)
Also,
Twelfth Term a(12) = a + ( 12 - 1) d
24 = a + 11d (2)
Now, let us subtract (1) from (2)
a + 11d = 24
(-)a +(-) 4d = (-)52
7d = -28
7d = -28
Common Difference (d) = -4
Now substituting value of d as -4 in (1)
a + ( 4 × -4 ) = 52
a + -16 = 52
a = 52 + 16 = 68
First Term (a) = 68
We know that the general format of an AP is a,a+d,a+2d,a+3d , .... a+nd
Here, Since
a = 68 and d = -4
The AP will become 68 , 68 + (-4) , 68 + 2(-4) , 68 + 3(-4) , 68 + 4(-4)
So, The AP is 68 , 64 , 60 , 56 , 52,.....
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