The fifth term of an App 17/6 and the ninth term is 25/6, what is the 12th term? pls can you show with workings
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In the AP, the 5th term is 17/6 and the 9th term is 25/6.
What is the 12th term?
a+4d = 17/6 …(1)
a+8d = 25/6 …(2)
(2) minus (1): 4d = 8/6 or d = 8/24 or 1/3
a = 17/6 -4/3 = 17/6–8/6 = 9/6 = 3/2
The 12th term is a+11d = (3/2)+11*1/3 = 9/6+22/6 = 31/6. Answer.
Step-by-step explanation:
hope helps u
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