the fifth term of an arithmetic sequence is 38 and ninth term is 66. find the 30th term of tis sequence?
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a⁵ = 38
a+4d= 38 .......1
a⁹ = 66
a+8d = 66 .....….….2
sub eq1 and eq2
-4d = -28
d= 7
put d in eq1
a+4×7 = 38
a= 38-28
a= 10
hence the 30th term of AP
a³⁰ = a+29d = 10+29×7 = 10+203 = 213
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