Question

the fig 11.6 shows two paths drown inside a rectengular field 50 m long ang and 35 m wide.The width of each path is 5 m.Find the area of shaded portion
​

Answer 1

Answer:

Step-by-step explanation:

Area of the shaded portion :

There are two rectangles and a square in this shaded portion. I have enclosed a diagram so that you can understand easily.

Length and breadth of rectangle ABCD are 50 m and 5 m respectively.

Area of rectangle ABCD = L × B

= 50 × 5

= 250 sq m

Length and breadth of the rectangle EFGH are 35 m and 5 m respectively.

Area of rectangle EFGH = 35 × 5

= 175 sq m

Length of each side of the square IJKL is 5 m.

Area of square = 5 × 5

= 25 sq m

Now, Area of the shaded portion = (Area of rectangle ABCD + Area of rectangle EFGH) - Area of square IJKL

= (250 sq m + 175 sq m) - 25 sq m

= 425 sq m - 25 sq m

= 400 sq m

So, the area of the shaded portion is 400 sq m.

Answer 2

$\huge \mathcal \red {\underline{\underline{A}}} \huge \mathcal \green {\underline{\underline{N}}} \huge \mathcal \pink {\underline{\underline{S}}} \huge \mathcal \blue {\underline{\underline{W}}} \huge \mathcal \orange {\underline{\underline {E}}} \huge \mathcal \purple {\underline{\underline{R}}} ✧$

Case :- 1

Dimensions of rectangle PQRS

PQ = 50 m

QR = 5m

Area of rectangle PQRS = PQ × QR = 50 × 5 = 250 m²

Case :- 2

Dimensions of rectangle EFGH

EF = 35 m

FG = 5m

Area of rectangle EFGH = EF × FG = 35 × 5 = 175 m²

Case :- 3

Dimensions of rectangle KLMN

KL = 5 m

LM = 5m

Area of square KLMN = KL × LM = 5 × 5 = 25 m²

So, area of shaded region is

Area of rectangle PQRS + Area of rectangle EFGH - Area of KLMN

= 250 + 175 - 25

= 400 m²

$\red{\textsf{(✪MARK BRAINLIEST✿)}} \\ \huge\fcolorbox{aqua}{aqua}{\red{FolloW ME}}$

$\huge \fcolorbox{black}{cyan}{♛Hope it helps U♛}$