Question

The Fig 5.15 shows a basic hydraulic system that has small and large pistons of cross section area of 0.005 m’and 0.1 mrespectively. A force of 20N is applied to small piston. Calculate a) The pressure transmitted into hydraulic fluid. b) The force at large piston. c) Discuss the distance travelled by small and large pistons. Load 20N 0.1m? 0.005m Small Piston Large Piston​

Answer 1

Answer:

20N/0.05m2=XN/0.10m2  

The surface is two times larger so the force is also two times larger. Also the distance the bigger piston moves is half the distance the small one moves.