Question

THE FIG SHOWS A P-V CLASS OF A THERMODYNAMIC BEHAVIOUR OF AN IDEAL GAS FIND OUT WORK DONEBY THE GASS A-B,B-C,C-D,D-A

Answer 1

Answer: Work done in the process A→B (the process is expansion, hence work done by the gas)

=−P×dV=−12×10

5

×5×10

−3

=−6000J

Work done in the process B→C is zero as volume remains constant.

Work done in the process C→D (the process is contraction hence work done on the gas)

=P×dV=2×10

5

×6×10

−3

=1000J

(ii) Work done in the process D→A is zero as volume remains constant.

Net work done in the whole cycle =−6000+1000=−5000J

i.e., net work is done by the gas.