Question

the figure ABII CD, transversal PQ intersects AB and CD at R and


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Answer 1

Answer:

Given :- AB||CD

PQ is transversal line

angle 1 : angle 2= 3:2

let , angle 1 = 3x

angle 2= 2x

Now, angle 1 + angle 2 = 180°

3x + 2x = 180°

= 5x = 180°

= x = 180

5

= x = 36°

angle 1 = 3x = 3×36 = 108°

angle 2 = 2x = 2×36 = 72°

angle 1 = angle 5

angle 2 = angle 6

angle 5 = 108° , angle 6 = 72°

angle 1 = angle 3

angle 2 = angle 4

angle 4 = 72° , angle 3 = 108°

angle 1 = angle 7

angle 2 = angle 8

angle 7 = 108°

So,

1,3,5,7 = 108°

2,4,6,8 = 72°

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