Question

the figure AC is the length of the pole standing vertical on the ground the pole is Ben at point B so that the top of the poet of these the ground at point 15 metres away from the base of the pole if the length of the pole is 25 metres find the length of the upper part of the pole​

Answer 1

Answer:

the height of the upper part of the Pole is 17 m

Answer 2

The length of upper part of the pole  BC = 17 m

Step-by-step explanation:

From the figure

Length of the pole AC = 25 m

Let AB = x  &  BC = AC - AB

⇒ BC = 25 - x = BC'

From pythagoras theorm

$(BC')^{2} = AB^{2} + AC' ^{2}$

$(25 -x)^{2} = 15^{2} + x^{2}$

$625 + x^{2} - 50 x = 225 + x^{2} \\50 x = 400\\x = 8 m$

Thus the length of upper part of the pole  BC = 25 - x

⇒ BC = 25 - x  = 25 - 8

⇒ BC = 17 m

Therefore the length of upper part of the pole  BC = 17 m