The figure alongside shows two concentric circles with a common centre O. Line m intersects the circles at points A, P, Q, and B, as shown in the figure. OL is a perpendicular drawn from the centre of the circle on line m. Prove that AP = QB.
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"I FOLLOWED MY HEART INTO THE FIRE GOT BURNED GOT BROKEN DOWN BY DESIRE I TRIED I TRIED BUT THE SMOKE IN MY EYES LEFT ME BLURRY BLURRY AND BLIND, I PICKER ALL THE PIECES UP OF THE GROUND I HAVE BURNED ALL MY FINGERS BUT THAT'S GONE NOW GOT THE GLUE IN MY HAND AND STICKING TO THE PLAN STICKIN TO THE PLAN THAT SAYS I CAN DO ANYTHING AT ALL , I CAN DO ANYTHING AT ALL"
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hope this helps
Step-by-step explanation:
let the inner circle be C1 and outer circle be C2
in C1
OL perpendicular PQ
OL BISECTS PQ (AS A PERPENDICULAR DRAWN FROM THE CENTRE OF THE CIRCLE TO A CHORD BISECTS THE CHORD)
PL = QL (1)
in C2
OL PERPENDICULAR AB
IN THE SAME WAY
AL = BL (2)
SUBTRACTING (1) FROM (2)
(2)-(1)
AL - PL = BL - QL
AP = QB
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