Question

The figure below is not drawn to scale, AB, CD and EF are straight lines. Find angle p.

Answer 1

Answer

A) ∠ABT=∠GHB=120

∘

(corresponding angles)

⇒AB∥GH

⇒[A] is correct.

B) ∠CDJ+∠IJD=180

∘

(supplementary angles)

⇒CD∥IJ

⇒[B] is correct.

C) ∠DEK=180

∘

−∠FEK=180

∘

−70

∘

=110

∘

But ∠DEK=∠CDJ=110

∘

(corresponding angles)

⇒DR∥SK

⇒[C] is correct.

D) inner∠EKL=360

∘

−outer∠EKL=360

∘

−260

∘

=100

∘

∠EKL+∠FEK=100

∘

+70

∘

=170

∘



=180

∘

⇒EF not∥ KL

⇒[D] is false.

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Answer 2

This is the answer

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