Math, asked by 362575, 8 months ago

The figure below shows a shaded rectangular region inside a large rectangle:

A rectangle of length 10 units and width 5 units is shown. Inside this rectangle is a smaller rectangle of length 4 units and width 2 units placed symmetrically inside the larger rectangle. The smaller rectangle is shaded gray.

What is the probability that a point chosen inside the large rectangle is not in the shaded region?

8%
16%
50%
84%

Answers

Answered by amitnrw
0

Given :   A rectangle of length 10 units and width 5 units  

Inside this rectangle is a smaller rectangle of length 4 units and width 2   units placed symmetrically inside the larger rectangle.

The smaller rectangle is shaded gray.

To Find : the probability that a point chosen inside the large rectangle is not in the shaded region?

8%

16%

50%

84%

Solution:

Area of rectangles  = 10 * 5 = 50 sq units

Area of shaded region = 4 * 2  = 8 sq units

Area not shaded = 50 - 8  = 42 sq units

probability that a point chosen inside the large rectangle is not in the shaded region = 42/50

= 0.84

= 84 %  

the probability that a point chosen inside the large rectangle is not in the shaded region is 84 %

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