Question

the figure below shows the cylindrical copper conductor along with their face area and length discuss in which geometrical shape the resistance will be high​

Answer 1

Answer:

See below.

Explanation:

We know that,

$\begin{aligned}R=\rho \dfrac {l}{A}\\ \Rightarrow R\propto \dfrac {l}{A}\end{aligned}$

So, we check the quantity l / A for every given conductor.

For ( 1 ),

$\dfrac {l}{A}=\dfrac {L}{A}$

For ( 2 ),

$\dfrac {l}{A}=\dfrac {2L}{\dfrac {A}{2}}=4\dfrac {L}{A}$

For ( 3 ),

$\dfrac {l}{A}=\dfrac {L/2}{2A}=\dfrac {1}{4}\dfrac {L}{A}$

We can clearly see that ( 2 ) has the highest value for L / A and hence exhibits the highest resistance.

The constant L / A is referred as cell constant it eletrochemistry.

Answer 2

Plzz. refer to the attachment for your solution.

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