Question

The figure below shows the velocity-time graph of a body moving in a straight
line.
Find:
(i) the time interval in which the body is moving with zero acceleration.
(ii) the total displacement of the body.​

Answer 1

Answer:

1) 12 seconds

2)240 metres

Explanation:

1)the velocity of object is constant upto 12 sec

2)to calculate the displacement we have to find the area of following figure

the figure is trapezium

area of trapezium= 1/2 ×(sum of parallel side) × height

= 1/2×(12+20)×15

= 240

Answer 2

i) form time 0 seconds to 12 seconds the acceleration is zero

ii) $s=240\ m$

Explanation:

i)

From the given figure we observe that the velocity does not changes with time and remains constant form time 0 seconds to 12 seconds. As we know by definition that acceleration is the rate of  change in velocity. So, during this time the acceleration is constant.

ii)

Total displacement of the body:

We know displacement is calculated as velocity multiplied with time taken.

We can here find the area under the curve to calculate the displacement.

$A=\frac{1}{2} (12+20)\times 15$

$A=240$

So we have the total displacement:

$s=240\ m$

#learnmore

TOPIC: velocity

https://brainly.in/question/10454184