Physics, asked by Anushkapurohit, 8 months ago

The figure below shows three cylindrical copper conductors along with their face areas and lengths compare the resistance and the resistivity of the three conductors justify your answer

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Answered by Anonymous
53

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# First Cylinder (a)

  • Length = L
  • Area = A

\Large{\sf{R \: = \: \rho \:  \frac{L}{A}}---(1)}

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# Second Cylinder (b)

  • Length = 3L
  • Area = A/3

Put Value in (1)

\Large \leadsto {\sf{R' \: = \: \rho \: \frac{3L}{\frac{A}{3}}}}

\Large \leadsto {\sf{R' \: =  \: \rho \: (\frac{9L}{A})}}

\LARGE \implies {\sf{R' \: = \: 9R}}

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# 3rd Cylinder (c)

  • Area = 3A
  • Length = L/3

Put Value in (1)

\Large \leadsto {\sf{R" \: = \: \rho \: \frac{L}{3(3A)}}}

\Large \leadsto {\sf{R" \: = \: \frac{1}{9} \:  \rho \: (\frac{L}{A})}}

\LARGE \implies {\sf{R" \: = \: \frac{1}{9} \: R}}

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Comparing according to resistance

R' > R > R"

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