Physics, asked by Anushkapurohit, 10 months ago

The figure below shows three cylindrical copper conductors along with their face areas and lengths compare the resistance and the resistivity of the three conductors justify your answer

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Answered by Anonymous
53

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# First Cylinder (a)

  • Length = L
  • Area = A

\Large{\sf{R \: = \: \rho \:  \frac{L}{A}}---(1)}

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# Second Cylinder (b)

  • Length = 3L
  • Area = A/3

Put Value in (1)

\Large \leadsto {\sf{R' \: = \: \rho \: \frac{3L}{\frac{A}{3}}}}

\Large \leadsto {\sf{R' \: =  \: \rho \: (\frac{9L}{A})}}

\LARGE \implies {\sf{R' \: = \: 9R}}

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# 3rd Cylinder (c)

  • Area = 3A
  • Length = L/3

Put Value in (1)

\Large \leadsto {\sf{R" \: = \: \rho \: \frac{L}{3(3A)}}}

\Large \leadsto {\sf{R" \: = \: \frac{1}{9} \:  \rho \: (\frac{L}{A})}}

\LARGE \implies {\sf{R" \: = \: \frac{1}{9} \: R}}

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Comparing according to resistance

R' > R > R"

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