Question

the figure diameter ab is 30cm chord AC is equal to 24 cm find how far is the cord AC from the centre of the circle​

Answer 1

Given:

Diameter ab is 30cm and chord AC is equal to 24 cm

To find : how far is the chord AC from the centre of the circle

Process:

∵ The perpendicular drawn from the centre to the chord bisects it.

∴ AM = 1/2 AB = 1/2 × 30 cm

= 15 cm

Also, OA = 1/2 AD

= 1/2 × 34 cm

= 17 cm

In rt. △OAM,

we have

OA2 = OM2 + AM2

172 = OM2 + 152

⇒ 289 = OM2 + 225

⇒ OM2 = 289 - 225

⇒ OM2 = 64

⇒ OM = √64 = 8 cm

Feel free to ask if u hv any doubt in procedure

Answer 2

Answer:

9 cm

Step-by-step explanation:

d=30 cm

r=15 cm

distance frm center to the chord = length of chord - r

=24-15

=9 cm