Question

the figure given below
e velocity-time graph of a particle moving along a straight line is shown in the figure in


The displacement of the particle in 5 second is
(1) 0.5 m
(3) 2 m
(2) 1 m
(4) 4 m​

Answer 1

Answer:

5 m

Explanation:

disp=area

=(3*2*1/2)+(1*2*1/2)+

(1*2*1/2)

=3+1+1=5 m

Even if due to second leg of negative velocity, we take second bracket as negative,

(3*2*1/2) - (1*2*1/2)+

(1*2*1/2)

gives us 3-1+1=3 m

which is not available in the four options.

Answer 2

Answer: 4m

Explanation:Name the triangles and rectangle in the graph. To calculate displacement from velocity time graph, find area enclosed by the graph. Area below time axis is negative.

In triangle ABC, area=1/2* 2*3=3m

Area of triangle CDE=1/2*1*2=1m

Area of rectangle EFGH= 1*2=2m

Displacement= 3+2-1=5-1=4 m