The figure given below, shows a circle with centre O. Given angle AOC = a and angle ABC = b. Find the measurement of angle OAB, if OABC is a parallelogram.
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it is given that oabc is a parallgelogram and we know that in a parallelogram opposite angles are equal
so angle ocb =oab
but angle oab+ocb =180°(opposite angle cyclic quadrilateral)
ocb+oab=180
2oab=180
oab=90°
but this answer seems like wrong
so angle ocb =oab
but angle oab+ocb =180°(opposite angle cyclic quadrilateral)
ocb+oab=180
2oab=180
oab=90°
but this answer seems like wrong
Lalith1111:
First of all it is not a cyclic qadrilateral since all the four vertices are not circumference of the circle
*not on
i know it
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hope it helps u well
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tqq plz. mark as brain list plzzz
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