Question

The figure given below shows a Pentagon ABCDE with
sides AB and ED parallel to each other and angle B angle :C angle: and angle D =5: 6: 7.
a)Using formula find the sum of interior angles of a pentagon.
b)Write the value of angle a + angle E.
c)Find angleB,C and D

Answer 1

Answer:

Step-by-step explanation:

(i) Sum of interior angles of the pentagon

= (5 – 2) × 180°

= 3 × 180° = 540° [∴ Sum for a polygon of a x sides = (x – 2) × 180°]

(ii) Since AB ∥ ED

∴ ∠A + ∠E = 180°

(iii) Let ∠B = 5x,  ∠C = 6x and ∠D = 7x

∴ 5x + 6x + 7x + 180° = 540°

(∠A + ∠E = 180°)

Proved in (ii)

18x = 540° – 180°

⇒ 18x = 360° ⇒ x = 20°

∴ ∠B = 5 × 20° = 100°, ∠C = 6 × 20 = 120°

∠D = 7 × 20 = 140°

Answer 2

Answer:

Sorry I didn't know what you say that