Question

The figure given below shows the cross-section of a concrete wall to be constructed. It is 2 m wide at the top, 3.5 m wide at the bottom and its height is 6m, and its length is 400 m. Calculate 2m (i) (ii) The cross-sectional area Volume of concrete in the wall​

Answer 1

Answer:

Area of crossection = A

1

+A

2

A

1

=0.9×5

=4.5m

2

A

2

=

2

1

(1)×5=2.5m

2

Area of crossection = 7m

2

Step-by-step explanation:

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Answer 2

Given :- The figure given below shows the cross-section of a concrete wall to be constructed. It is 2 m wide at the top, 3.5 m wide at the bottom and its height is 6m, and its length is 400 m.

To Find :-

• The cross-sectional area .
• Volume of concrete in the wall .

Solution :-

from image we can see that, the cross-section of a concrete wall is in the shape of a trapezium .

so,

→ Cross section area = Area of trapezium

→ Cross section area = (1/2) * (sum of parallel sides) * height

→ Cross section area = (1/2) * (2 + 3.5) * 6

→ Cross section area = 3 * 5.5

→ Cross section area = 16.5 m²

then,

→ Volume of concrete in the wall = Cross section area * Length

→ Volume of concrete in the wall = 16.5 * 400

→ Volume of concrete in the wall = 6600 m³

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