Question

the figure given below shows three resistor ​

Answer 1

Refer to the attachment

$from \: the \: calculation \: we find \: the \: total \: resistance \: if \: the \: circuit \: is \: \\ 7 \: ohm$

Note :

$1)parallal \: resistance \: calculation \: formula \\ = > r \: = ( \frac{1}{r1} + \frac{1}{r2} + ... + .) ^{ - 1} \\ \\ 2)series \: coimbintion = r1 + r2 + .....$

Answer 2

Answer:

your answer is (c)

Explanation:

first we have to check the resultant resistance for parallel series

so, 1/R = 1/R1 + 1/R2

= 1/6 + 1/2

= 1/6 + 3/6

= 4/6

= 2/3

now we should go for the series combination

so, R = R1 + R2

= 2/3 + 6

= 20/3

= 6⅔ ohms