the figure given shows two identical semicircles cut from a piece of coloured paper find the area of the remaining piece of paper
Answers
Answer:
let's consider the semicircles as a whole circle ..then are of trapezium- area of circle is :
1/2(7+19)×20 - 22/7× 7²
260- 154
answer =106
hence the area of remaining part is 106 sq.cm
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Concept:
A quadrilateral is a shape with four sides and one set of parallel sides, and a trapezium is one of these shapes. The region enclosed by these four sides is hence the trapezoid's area. The height of the trapezium and the length of its parallel sides have the biggest impact on its area. Square units are used to measure it.
Area = (1/2) h (a+b)
where,
a and b are the length of parallel sides
h is the height or distance between parallel sides.
A circle's area is the area that it takes up in a two-dimensional plane. It can be simply calculated using the formula A = πr², (Pi r-squared), where r is the circle's radius. The square unit, such as m², cm², etc., is the unit of area.
Circle area = π r² or πd²/4, in square units.
which equals 22/7 or 3.14
Given:
Figure of a trapezium with two semicircles cut from it
Find:
Find the area of the remaining piece of paper
Solution:
As per question,
Area of remaining portion= ARea of trapezium - Area of 2 semicircle
=ARea of trapezium - Area of 1 circle
= 1/2 (sum of parallel sides) height - π x radius²
= 1/2(7+19)×20 - 22/7× 7²
= 260- 154
=106 cm²
Therefore, the area of remaining part is 106 sq.cm
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