The figure here shows a proton p and an electron e on an x axis.What is the direction of the electric field due to the electron at (a) point S and (b) point R? What is the direction of the net electric field at (c) point R and (d) point S?
Answers
Explanation:
(d)pointS?(A)At point S if we put an imaginary + charge then the electron (e) willattract it so the direction of electric field will berightward. (B) If positivecharge is put at R point then the direction will beleftward. (C) The directionof net electric field at point R will beleftwardbecause electron(e) willattract the imaginary point charge at point R and proton(p) will repeal theimaginary point charge.(D) If we imagine a positive charge at point S thenelectron will attract it so the direction will be rightward. But proton(p) willrepeal it so the direction will be leftward. As the distance between S andelectron(e) is less than the distance between S and proton(p) then thedirection of net electric field at point S will berightward.
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