Question

The figure Is made up of a circle, with centre A, And two identical right-angled triangles. The radius of the circle is 10cm. Find the area of the shaded part of the figure.( take PI as 3.14)

Answer 1

Answer:

214 sq cm

Step-by-step explanation:

Given :-

• Redius of Circle = 10 cm
• Two right triangle
• Where π=3.14

Solution:-

Area of Circle =

$\pi {r}^{2} = 3.14 \times {10}^{2} \\ 3.14 \times 100 = 314 \: {cm}^{2}$

Area of both triangle =

$2 \times (\frac{1}{2} \times base \times hight) \\ 2( \frac{1}{2} \times 10 \times 10) \\ 2(50) \\ 100 {cm}^{2}$

Now Area of Shaded region = Area of Circle - Area of both Triangle

= 314-100 = 214 sq cm