Question

The figure shows a capacitor made of two circular plates each of radius 12 cm and separated by 4.0 mm. The capacitor is being charged by an external source not shown in the figure. The charging current is constant and equal to 0.15A. The capacitance of capacitor is

Answer 1

Answer:

Given,

Given, R = 12cm=0.12md=5.0mm=5×10−3I=0.15Aε0=8.85×10−12C2N−1m−2A=πR2=3.14×(0.12)2m2

Capacitance of parallel plate capacitor is given by

C=ε0Ad=8.85×10−12×(3.14)×(0.12)25×10−3=80.1×10−12=80.1pF.

Now,

qdqdt=CV=C×dVdt

or,

I=C×dVdt[∵I=dqdt]

or, dVdt=IC=0.1580.1×10−12

=1.87×109Vs1 .

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