The figure shows a circle of radius 14 cm with one quadrant removed, touching the
sides of a square. Find
(1) the perimeter of the unshaded region,
(ii) the area of the unshaded region,
(iii) the area of the shaded region.
Answers
Solution:
(i) Perimeter of the unshaded region = perimeter of square - circumference of circle + perimeter of 2 sides
= 4×28 - 2 π ×14+2(14) [2r=side of square]
= 112 - 2(22/7)× 14 + 28
= 112 -88 +28
= 52 cm
(ii) The Area of unshaded region = Area of circle - Area of quadrant
= π (14)² - 1/4 π(14)²
= 22/7 × 14 × 14 - 1/4 × 22/7 × 14 × 14
= 616 - 154
= 642 cm²
iii) The Area of Shaded region = Area of Square - Area of unshaded region
= (28)² - 642
= 784 - 642
= 142 cm²
Answer
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