Math, asked by kingaahhmmeedd1122, 2 months ago

The figure shows a circle of radius 14 cm with one quadrant removed, touching the
sides of a square. Find
(1) the perimeter of the unshaded region,
(ii) the area of the unshaded region,
(iii) the area of the shaded region

Answers

Answered by Anonymous
2

(i) Perimeter of the unshaded region = perimeter of square - circumference of circle + perimeter of 2 sides =4x28-2π × 14+2(14) [2r=side of square]

=112 - 2(22/7)* 14 + 28

=112 -88 +28

=52 cm

(ii) The Area of unshaded region = Area of circle - Area of quadrant

=1 (14)² - 1/4 π (14)²

=22/7 × 14 × 14 - 1/4 × 22/7 × 14 × 14

=616 - 154

=642 cm²

(iii) Area of Shaded region = Area of square- Area of unshaded region

= (28)² - 642

= 784 - 642

= 142 cm²

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