The figure shows a parallelogram PQRS of area given by 35 cm². If T is a point on QR such that QT = 4 cm and TR = 3 cm, find the area of ∆PQT.
Answers
Answered by
17
For a parallelogram,
▶Opposite sides are equal.
Given,
Area of parallelogram = 35 cm^2.
Length of QR = RT + TQ
Length of QR = 7
We know ,
Area of parallelogram = base × height
Base = PQ = ?
Height = QR = 7cm
So,
35 = base ×7
35/7 = base
5cm = base
For ΔPQT
Base = PQ = 5cm
Height = QT = 4cm
Area of triangle = 1/2 × base × height
Area of triangle = 1/2 × 7 × 4
Area of triangle = 1/2 × 28
Area of triangle =14 cm^2
▶Opposite sides are equal.
Given,
Area of parallelogram = 35 cm^2.
Length of QR = RT + TQ
Length of QR = 7
We know ,
Area of parallelogram = base × height
Base = PQ = ?
Height = QR = 7cm
So,
35 = base ×7
35/7 = base
5cm = base
For ΔPQT
Base = PQ = 5cm
Height = QT = 4cm
Area of triangle = 1/2 × base × height
Area of triangle = 1/2 × 7 × 4
Area of triangle = 1/2 × 28
Area of triangle =14 cm^2
Similar questions