Question

The figure shows a parallelogram PQRS of area given by 35 cm². If T is a point on QR such that QT = 4 cm and TR = 3 cm, find the area of ∆PQT.

Answer 1

For a parallelogram,

▶Opposite sides are equal.

Given,

Area of parallelogram = 35 cm^2.

Length of QR = RT + TQ

Length of QR = 7

We know ,

Area of parallelogram = base × height

Base = PQ = ?

Height = QR = 7cm

So,

35 = base ×7

35/7 = base

5cm = base

For ΔPQT

Base = PQ = 5cm

Height = QT = 4cm

Area of triangle = 1/2 × base × height

Area of triangle = 1/2 × 7 × 4

Area of triangle = 1/2 × 28

Area of triangle =14 cm^2