Question

the figure shows a pentagon ABCDE is drawn parallel to DJ mix BA produced at ji and CF draw parallel to DB meet Savi produced at F show the area of Pentagon ABCDE barabar area dgf.

Answer 1

Hey buddy here is ur half solution


Lets concentrate on the quadrilateral ADEG.
let the intersection of AE and DB be K
GE || AD (given)
So triangles ADE and ADG have the same base AD and the same height , since parallel lines are equal distances apart.
So triangle ADE = triangle ADG
but ADK is common to both, so subtracting ...
triangle AKG = triangle DEK

similarly by letting FD and BC intersect at L we can show that triangle FLB = triangle CDL

pentagon ABCDE
= triangle BLD + triangle LCD + triangle ABD + triangle DEK + triangle ADK
= triangle BLD + triangle FLB + triangle ABD + triangle GAK + triangle ADk
= triangle FDG .



plz solve by own

Answer 2

Answer:

hope this answer useful to you mate