The figure shows a ray of light passing through a prism. If the refracted ray QR is parallelt
the base BC, show that
i. r1 = r2 = 4 and
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Complete question:
Figure shows a ray of light passing through a prism. If the refracted ray QR is parallel to the base BC, show that (i) r₁ = r₂ = A/2 and (ii) angle of minimum deviation, Dm = 2i - A
Solution:
(i) If the refracted ray QR is parallel to the base BC, then i = e
r₁ = r₂ = r
We know that,
r₁ + r₂ = A
r + r = A
2r = A
r = A/2
Therefore, r₁ = r₂ = A/2
Hence proved.
(ii) A + D = i + e
Since i = e, so D = Dm
A + Dm = i + i
A + Dm = 2i
Dm = 2i - A
Hence proved.
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