Question

The figure shows a rhombus and an equilateral triangle joined together. Find (a) ∠C (b) ∠ABD (c) ∠E (d) ∠A

Answer 1

Answer:

/_ C = 60° as all sides are equal

/_ABD=120° Linear pair

/_E =120° opposite angles are equal

/_ A= 60° 360°- (120°+120°)

=360°-240°=120°

=120÷2=60°

Answer 2

Step-by-step explanation:

B

21

∘

,31

∘

∠BAD=180−78=102

0

In triangle ABC, ∠BAC=∠BCA=51

0

[ABC is an isosceles triangle]

In triangle EDC, angle EDC is 60+78=138

0

So, ∠DCE=∠DEC=21

0

We know angle BCA is 102

0

Out of which angle BCA is 51 deg and angle DCE is 21 deg

Hence the remaining angle, angle ACE is 102−(51+21)=30

0

∠DCE=21

0

∠ACE=30

0