Question

The figure shows a rhombus with its sides as indicated. Find the perimeter of the figure.​

Answer 1

Answer:

since,the sides of rhombus are equal,

2x+y+1=x-y=(3x-y-2)/2

2x+y+1=x-y

x+2y=-1

x=-1-2y ...(i)

then,

x-y=(3x-y-2)/2

2x-2y=3x-y-2

2x+y=2

2(-1-2y)+y=2

-2-4y+y=2

-3y=4

y=-4/3

then put value of y in eqn(i)

x=5/3

then find the value of one side using these values and find perimeter using the formula

Answer 2

The perimeter of rhombus =32 cm

Step-by-step explanation:

Given sides of rhombus are

(2x+y+1) cm,(x-y) cm and ($\frac{3x-y-2}{2}) cm$

We know that all sides of rhombus are equal

Therefore,

$x-y=2x+y+1$

$2x+y-x+y=-1$

$x+2y=-1$....(1)

$x-y=\frac{3x-y-2}{2}$

$2x-2y=3x-y-2$

$3x-y-2x+2y=2$

$x+y=2$....(2)

Subtract equation (1) from (2)

$y=-3$

Substitute the values of in equation (1)

$x+2(-3)=-1$

$x-6=-1$

$x=-1+6=5$

Substitute the values of x and y

Side of rhombus=$x-y=5-(-3)=5+3=8cm$

Perimeter of rhombus=$4\times side=4\times 8=32 cm$

Hence, the perimeter of rhombus =32 cm

#Learns more:

https://brainly.in/question/2498203:Answered by suprihi