Question

The figure shows a trapezium ABCD where
AB=5 m, BC = 6 m, CD = 13.2 m and AD = 5.5 m.
13.2 m
D
E
5.5 m
If AE = 4 m, find
(1) the area,
(2)in the perimeter
of the trapezium.
4 m
6 m
А
B.
5 m​

Answer 1

Answer:

Area of the trapezium = 36.4m²

Perimeter of the trapezium = 29.7cm

Step-by-step explanation:

Correct Question :-

The figure shows a trapezium ABCD where AB=5 m, BC = 6 m, CD = 13.2 m and AD = 5.5 m   , AE = 4 m, find

(1) the area,

(2)in the perimeter  of the trapezium.

Given,

ABCD is a trapezium

AB = 5m

BC = 6m

CD = 13.2m

AD = 5.5m

AE = 4m

To Find :-

Area and perimeter of the trapezium

Formula Required :-

$Area\:of\:trapezium=\dfrac{Sum\:of\:parallel\:sides}{2}\times height$

$=\dfrac{a+b}{2}\times h$

$Perimeter\:of\:the\:trapezium=Sum\:of\:its\:all\:sides$

Solution :-

Parallel sides of the trapezium (a , b)= AB , CD

Height of the trapezium (h) = AE

$Area=\dfrac{5m+13.2m}{2}\times 4m$

$=\dfrac{18.2m}{2}\times 4m$

$=9.1m\times 4m$

= 36.4m²

∴ Area of the trapezium = 36.4m²

$Perimeter=AB+BC+CD+DA$

= 5m + 6m + 13.2m + 5.5m

= 11m + 18.7m

= 29.7m

∴ Perimeter of the trapezium = 29.7cm

Note : Refer above picture