Physics, asked by manjugangwar8448, 8 months ago

The figure shows elliptical orbit of a planet m about the
sun S. The shaded area SCD is twice the shaded area SAB.
If t₁ is the time for the planet to move from C to D and t₂ is
the time to move from A to B then :
(a) t₁ = 4t₂ (b) t₁ = 2t₂
(c) t₁ = t₂ (d) t₁ > t₂

Answers

Answered by ReRepeater
2

Answer:

(b) t₁ = 2t₂

Explanation:

Kepler's 2  nd  law

dA /dt =constant

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