Question

The figure shows elliptical orbit of a planet m about the Sun s.The shaded area SCD is twice the shaded area SAB .If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then:
a)t1=4t2 b)t1=2t2 c)t1=t2 d)t1>t2

Answer 1

Ans is b part because areal velocity is constant and hence for double area double time is required

Hope it helps☺

Answer 2

Equal areas are swept in equal time , the time taken to go from C and B =  

where   is the time taken to go from A to B  

As it is given that area SCB = 2SAB