the figure shows the acceleration versus time graph the particle starts from rest at t=0 Find the approximate velocity at t=1 sec
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Area under a−t graph is change in velocity
Area=
2
1
(4×4)+6×4+
2
1
×2×4−
2
1
×2×2
=36−2
=34m/s
As initial velocity is zero therefore, the velocity at 14 second is 34m/s
Area=
2
1
(4×4)+6×4+
2
1
×2×4−
2
1
×2×2
=36−2
=34m/s
As initial velocity is zero therefore, the velocity at 14 second is 34m/s
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