Question

The figure shows the velocity time graph of a
particle moving in a straight line. Mass of the
particle is 4 kg. Find the work done by the
force acting on the particle in time interval
between t = 0 to t= 10 second​

Answer 1

Answer:  300J

From work-energy theorem,

W=ΔKE=Kf−Ki=12m(v2f−v2i)

=12×2[(−20)2−(10)2]=300J

hope it helps u !