Physics, asked by aditi2608, 8 months ago

the figure shows two rays A and B travelling from water to air. If the critical angle for water-air surface is 48°, complete the ray diagram showing the refracted rays for each. state conditions when the ray will suffer total internal reflection​

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Answered by flambointJr
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Asked on October 15, 2019 by

Tejo Gabbar

A ray of light travels from water to air as shown in the diagram given.

(i) Copy the diagram and complete the path of the ray. Given the critical angle for water is 48

o

.

(ii) State the condition so that total internal reflection occurs in the diagram.

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ANSWER

The path of each is ray is shown in the above diagram when they pass through the air-water interface.

(i) : Since the critical angle for water air surface is 48

o

. So the rays, for which angle of incidence is less than 48

o

, will get refracted at the surface. While the ray for which angle of incidence is greater than 48

o

will get total internally reflected.

Also, the given has angle of incidence exactly as 48

o

. So it grazes over the water air interface as shown.

(ii) : There are two condition for total internal reflection to occur.

(a) : The light ray must travel from denser medium to rarer medium but not vice- versa.

(b) : Angle of incidence of the ray must be greater than the critical angle. So total internal reflection of ray will occur is ∠i>48

o

.

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