Question

The filament of an electric bulb draws a current of 0.4A , which lights for 3 hours. Calculate the amount of charge that flows through the circuit.

Answer 1

I=Q
__
T
0.4 = Q/10800
(t=3×3600=10800)
Q =10800×0.4=4320


so the charge is 4320 coulomb.

Answer 2

The amount of charge flowing through the circuit is 4320 C

Given:

Current or I= 0.4 A  

Duration of the electric bulb lights = 3 hours

To find:

The amount of charge flowing through the circuit.

SOLUTION:

Charge is given by Q and is calculated by the formula: $\mathrm{Q}=I \times \mathrm{t}$

Time has to calculated in seconds, so we get

$t= 3 \times 3600$ = 10800 sec

$\mathrm{Q}=0.4 \times 10800=4320 \mathrm{C}$ where,C is the Coulomb which is unit of charge.

Therefore, The amount of charge which flows through the circuit is found to be 4320 C