The filament of an electric lamp draw a current of 0.8 ampere which lights for 5 hours. calculate the amount of charge that flow through the circuit.
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I = 0.8A
T = 5 HOURS = 5*3600 = 18000 SEC.
I=Q/T SO Q=IT
Q= 0.8*18000 = 14,400
T = 5 HOURS = 5*3600 = 18000 SEC.
I=Q/T SO Q=IT
Q= 0.8*18000 = 14,400
Answered by
4
u do it yourself
I tell u formula
I=q/t
I tell u formula
I=q/t
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