Question

the filament of an electric lamp draws a current of 0.4A which lights for 3 hours. calculate the amount of charge that flows through the circuit​

Answer 1

Answer:

given,

i = 0.4 amperes

t = 3hrs=3 *60*60 = 10800 sec

q =?

formula :

q =i t

q =0.4 * 10800

=4320 coloumbs

Answer 2

Answer:

Explanation:

Current in the electric lamp = I = 0.4A

Duration of the lamp = t = 3h = 3 × 60 × 60 s = 10800s

Charge in the lamp = Q=?

Average current = total charge flowing through the cross sectional area of wire/ the time taken to flow

Hence, the amount of charge flowing through the circuit -

I = Q/t

Q = It, hence -

= 0.4 × 10800

= 4320C

Thus, if a filament of an electric lamp draws a circuit of 0.4a which lights for 3 hours. then the amount of charge that flows through the circuit is 4320C.