Question

The filament of an electric lamp,which draws a current of 0.25A is used for four hours. calculate the amount of charge flowing through the circuit

Answer 1

Do you know the formula that I=Q/T i.e. electric current equals charge flowing through a normal cross - sectional part in per unit time.
So, I=0.25 A , T= 4 hours and Q = we have to find.So Q =IXT i.e. 0.25X4 = 25/100*4= 1 coulomb of charge flowing through the circuit.
This is your answer mate!!!!!

Answer 2

Given :

Current = 0.25 A

Time = 4 hours = 4 × 60 × 60 = 14400 sec

To Find :

Amount of charge flowing

Solution :

We know, Current is the rate of flow of charge in a conductor. So,

   Current (I)     = $\frac{Charge (Q)}{Time (T)}$

Here, current (I) = 0.25 A and Time = 14400 sec

⇒     0.25          = $\frac{Charge (Q)}{14400}$

⇒   Charge (Q) = 14400 × 0.25

⇒   Charge (Q) = 3600 C

Therefore, the amount of charge flowing through the circuit  is found to be 3600 C.